Math, asked by shashankshekhar29, 2 months ago

5 cos^ 2 60^ +4 sec^ 2 30^ -tan^ 2 45^ / sin^ 2 30^ +cos^ 2 30^​

Answers

Answered by rozzah74
1

Answer:sin30

=1/2⇒sin

2

30

=1/4

cos45

=1/

2

=sin45

cot45

=1⇒cot

2

45

=1

cos60

=1/2⇒sec60

=2⇒sec

2

60

=4

cos30

=

3

/2⇒sec30

=2/

3

⇒sec

2

30

=4/3

cosec45

=1/sin45

=

2

⇒cosec

2

45

=2

(sin

2

30

+4cot45

−sec

2

60

)(cosec

2

45

sec

2

30

)

=[(

2

1

)

2

+4×(1)

2

−(2)

2

][(

2

)

2

×(

3

2

)

2

]

=1/4×8/3

=2/3.

Step-by-step explanation:

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