5 cos theetha + 12 sin theetha =13
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i am using x in case of theeta-------------
5 cose x = 13 -12 sin x
squaring on both sides we get ,
25 cos(power 2)x=169+144 sin (power 2)-312 sin x
in case of cos square x we substitute ( 1- sin square x, )as sin square x +cos square x = 1
equation will be 169 sin square x -312 sin x+144 =0
after using quadratic formula we get sin x = 312/338
so sin x = 12/13
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