Question

5 cos²60°+4 sec²30°-tan²45°÷sin²30°+cos²30°

Answer 1

 · ( 5 cos²60°+4 sec²30°- tan²45°) ÷ (sin²30° +cos²30°) = {5*(1/2)^ 2+ 4 (√3/2)^2-(1)^2} ÷{ (1/2)^2+(√3/2) ^2} ={ 5/4+4*(3/4)-1}