Question

5 cosA= 4sinA then tan A is​

Answer 1

5 cosA= 4sinA

5/4 = sinA/cosA

tan A = 5/4

Answer 2

Given:

• 5 cosA= 4sinA

To find :

• tan A

Formula used :

• tan x= sinx/cosx

Solution :

⇒5 cosA= 4sinA

⇒(5/4) cosA= sinA

⇒(5/4) = sinA/cosA

We know that :- sinA/cosA = tan A

Therefore :-

⇒5/4= tan A

Answer : 5/4

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Learn more:-

1. Cosθ = base / hypotenuse

2. cossecθ = 1/ sinθ

3. sec θ = 1/cosθ

4. Cotθ = 1/ tanθ

5. Sin²θ+ Cos²θ= 1

6. Sec²θ - tan²θ = 1

7. cosec ²θ - cot²θ = 1

8. sin(90°−θ) = cos θ

9. cos(90°−θ) = sin θ

10. tan(90°−θ) = cot θ

11. cot(90°−θ) = tan θ

12. sec(90°−θ) = cosec θ

13. cosec(90°−θ) = sec θ

14. Sin2θ = 2 sinθ cosθ

15. cos2θ = Cos²θ- Sin²θ