5 cubes each of volume 1728 m^3 are joined end to end .find the Csa of the resulting cuboid.
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Volume of each cube=1728cm³
a³=12³
→a=12
side of each cube =12cm
if we join5 such cubes end to end,
length=12+12+12+12+12=60cm
breadth=12cm
height=12cm
Lateral surface area of resulting cuboid=2h(l+b)
=2(12)[60+12]
=24×72
=1728cm²
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