Question

5. Daniel is painting the walls and ceiling of a
cuboidal hall with length, breadth and height
of 15 m, 10 m and 7 m respectively. From
each can of paint 100 m square of area is painted.
How many cans of paint will she need to paint
the room?
7 cm
7 cm
7 cm

Please tell me fast
This is the question of class 8 maths exercise 11.3​

Answer 1

Answer:

Surface area of a cuboidal hall without bottom = Total surface area – Area of base

= 2 [lb + bh + hl] – lb

= 2 [15 × 10 + 10 × 7 + 7 × 15] – 15 × 10

= 2[150 + 70 + 105] – 150

= 2 [325] – 150

= 650 – 150

= 500 m2

Area of the paint in one can = 100 m2

Number of cans required = 500100 = 5 cans.