Question

5. Daniel is painting the walls and ceiling of
cuboidal hall with length, breadth and hei
of 15 m, 10 m and 7 m respectively. From
each can of paint 100 m² of area is painted.
How many cans of paint will the need to paint
the room?​

Answer 1

Answer:

Step-by-step explanation: length=15m

                                              breadth=10m

                                              height=7m

area of  the inner wall= 2×(l+b)×h

                                      =2×(15+10)×7

                                     =2×25×7

                                    =350$m^{2}$

area of the celling= l× b

                                15m×10m

                              =150$m^{2}$

total surface area has to be painted=350+150$m^{2}$

                                                           =500$m^{2}$

  since    100$m^{2}$ we need 1 can of paint

therefore 1$m^{2}$                  $\frac{1}{100}$ can

         for 500$m^{2}$               $\frac{1}{100}$×500

                                        =5 can

Answer 2

Answer:

5 cans is thr answer............ xd