Question

5) Determine whether the triangle whose lengths of sides are 6cm, 8cm and
10cm is a right angled triangle.

Answer 1

Answer:

Yes

Step-by-step explanation:

Let H=10 cm,P=8 cm,B=6 cm.

By Pythagoras theorem,

H²=P²+B²

10²=8²+6²

100=64+36

100=100

Hence, it is right angled triangle.

Answer 2

The triangle with sides 6cm, 8cm and 10cm is a right angled triangle.

Given: Length of sides = 6cm, 8cm and 10cm.

To Prove: The triangle is right angled triangle.

Solution:

In right angled triangle, the relation between base, height and hypotenuse is: $Hypotenuse^{2} =Base^{2} +Height^{2}$.

As, we know that the largest side, so 10cm will be the hypotenuse.

We have to check whether the relation $Hypotenuse^{2} =Base^{2} +Height^{2}$is correct or not for this triangle.

$10^{2} =6^{2} +8^{2}$

100 = 36+64

100 = 100

Hence proved, that the triangle whose lengths of sides are 6cm, 8cm and 10cm is a right angled triangle.

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