Question

5 distinct positive common integers are in AP with a positive common difference . If the sum is 10020 then the smallest possible value of last term is ?

Answer 1

let the numbers be..

a-2b, a-b, a, a+b , a+2b

sum= 5a= 10020

a=2006..

hence the smallest value of last term is 1..

Answer 2

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Here's your answer

Let the numbers be..
a-2b, a-b, a, a+b , a+2b

sum= 5a= 10020
a=2006..

hence the smallest value of last term is 1.

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