Question

5. Divide: 24y3 - 8y2 +2y-3 by 2y-3. Write
quotient and remainder obtained and hence verifi
that dividend = divisor x quotient + remainder.​

Answer 1

Step-by-step explanation:

(24y^3-8y^2+2y-3) ÷(2y-3)

(12y^2) +(14y) +(22)

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(2y-3)√ ( 24y^3 -8y^2 + 2y - 3)

-(24y^3 -36y^2)

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0 + 28y^2 + 2y -3

-(28y^2 - 42y)

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0 + 0 + 44y - 3

-( 44y -66 )

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0 + 0 + 0 +63

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Quotient (q) = ( 12y^2 + 14 y + 22 )

remainder (r) = 63

divisor (d) = (2y-3)

divident (D) =(24y^3 - 8y^2 + 2y - 3) -----/1

D= (d*q) + r

D = {( 2y-3) * ( 12y^2 + 14y +22)} +63

D= { 24y^3 - 8y^2 +2y -66 } + 63

D= 24y^3 - 8y^2 + 2y -3 -------/2

comparing eq 1,2 we get same value for D

hence proof

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