5. Division 10A has 17 boys 23 girls. Division 10b
18 boys and 23 gires. To Select a girl leader
from the total number of children in both
division. What is the probability?
give step also
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Answer:
if you would like mark as brainlist
Step-by-step explanation:
sum of all students in each division
17+23+18+23=81
sum of girls in each division
23+23=46
now probability
no. of favourable outcomes ÷ no. of total outcomes
46/81
answer
point to remember
if in probability outcomes numerator and denominator both if at time of division you can easily solve them you should but if answer comes in point leave it there and that is only your answer
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