5 dm3 of nitrogen is mixed with the required quantity of hydrogen to give ammonia. calculate the volume of the hydrogen required and the volume of ammonia formed.
Answers
One mole of N2 reacts with 3 moles of hydrogen to form 2 moles of ammonia.
one mole of a gas occupies 22.4 litres at STP. Since there are 6 litres of Hydrogen, then there are 6/22.4 moles of H2. Then there are 1/3rd of that ie., 2/22.4 litres of Nitrogen that react with H2.
Then the number of moles of ammonia formed is = 2 * 2/22.4 = 4/22.4 moles.
The volume of ammonia = 4/22.4 * 22.4 litres = 4 litres.
Answer:
One mole of N2 reacts with 3 moles of hydrogen to form 2 moles of ammonia.
one mole of a gas occupies 22.4 litres at STP. Since there are 6 litres of Hydrogen, then there are 6/22.4 moles of H2. Then there are 1/3rd of that ie., 2/22.4 litres of Nitrogen that react with H2.
Then the number of moles of ammonia formed is = 2 * 2/22.4 = 4/22.4 moles.
The volume of ammonia = 4/22.4 * 22.4 litres = 4 litres.
Explanation: