Math, asked by rajniapya, 5 months ago

(5) Draw PQ = 6 cm. At point P, draw PS perpendicular to PQ such that PS = 5.5 cm. Through S, draw
RS || PQ with construction.

Answers

Answered by devilgirl239
3

Step-by-step explanation:

The angle bisectors meet at point S. This point of concurrence of the angle ... With P as centre and 4.5 cm as the radius, draw an arc above the line PQ.

Answered by mohanyadav10784
2

Answer:

Step I: Draw a line PQ and take a point R on it.

Step II: With R as centre and a convenient radius construct an arc touching the line PQ at two points A and B.

Step III: With A and B as centres and a radius greater than RA construct two arcs cutting each other at S.

Step IV: Join RS and extend it in both directions to get a line perpendicular to PQ.

Thus, XY is the line required which is perpendicular to PQ and passes through R as shown in the above image.

Step-by-step explanation:

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