5) During a trekking activity of 6km a student Ram will go to Sangam and return back up to 12
noon. He estimates that he can go to the Sangam at 1.5km/h on average, and return at half
that speed. These speeds take into account breaks and rest times. Using Ram's estimated
speeds, what is the latest time he can begin his walk so that he can return by 12 noon?
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Answer:
- dude...
Step-by-step explanation:
- one way = 6/2 = 3km
- time = 3/1.5+3/1.5/2
- time =2+ (3/1.5)*2
- time = 2 + 4
- time = 6 hrs...
- So, estimated starting time = 12.00-6.00 = 6 am
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