Question

5 electric bulb of 9 watt each used for 9 hr only two bulbs and rest of 3 used for 7 hr,2 fans of 60watt each used for 8 hr ,1 room heater of 2000watt used for 3 hrs and electric motor used for 2 hr. find the amount will be paid by the consumer in a month.
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Answer 1

Answer:

Given : t=6 hrs

P=0.06 kW

Thus energy consumed per day is:

E=Pt=0.06×6=0.36 kWh=0.36 units

Answer 2

Explanation:

Given : P=0.1 kW t=1 hour per day

Energy consumed per day E=Pt=0.1×1=0.1 kWh per day

Total energy consumed per month E

T

=30×0.1=3 kWh per month

Cost of electricity =Re 1 per unit i.e per kWh

∴ Monthly bill =Re. 1×3=Rs. 3 per month