Question

(5) Eleven bags of wheat flour, each marked 5 kg, actually contained the following
weights of flour (in kg).
4.97,5.05,5.08,5.03, 5.00,5.06,5.08,4.98,5.04,5.07,5.00.
Find the probability that any of these bags chosen at random contains more than
5 kg. of flour.​

Answer 1

Answer:

Given bag of wheat flour are

4.97,5.05,5.05,5.03,5.00,5.06,5.08,4.98,5.04,5.07,5.00

The total number of wheat flour bags =11.

The number of wheat flour bags contain more than 5 Kg are 7.

Then probability of bags chosen at random

$= \frac{number of bags more than 5 kg }{total \: number \: of \: bags} = \frac{7}{11}$

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