5. Express each of the following in terms of
trigonometric ratios of angles, lying between 0°
and 45°:
(i) sin 58° + cos 53°
(ii) tan 63° + cot 59°
(iii) sec 74° + cosec 51°
(iv) cos 77° + sin 77°
(v) sin 720 + coser 540
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Answer:
relative density of liquid
= density of liquid / density of water
= buoyancy force in liquid / buoyancy force in water
= Loss of weight in liquid / loss of weight in water
= [ weight of object in air - weight of object in liquid ] / [ weight of object in air - weight of object in water ]
= [ 75 - 70.5 ] / [ 75 - 66 ]
= 4.5 / 9
= 0.5
Density of liquid = 0.5 * density of water
= 0.5 * 1000 kg / m^3
= 500 kg/m^3
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