Math, asked by charshuchhabda563, 4 months ago

5. Express each of the following squares as sum of odd numbers:
(1) 25
(11) 36
(iii) 49
(v) 81
(iv) 64
(vi) 100

Answers

Answered by mannanreema41
4

Answer:

(i) 25

n=5

now, 1++3+5+7+9=(5)²=25

(ii) 36

n=6

now, 1+3+5+7+9+11=(6)²=36

(iii) 49

n=7

now, 1+3+5+7+9+11+13=(7)²=49

(iv) 64

n=8

now, 1+3+5+7+9+11+13+15=(8)²=64

(v) 81

n=9

now, 1+3+5+7+9+11+13+15+17=(9)²=81

(vi) 100

n=10

now, 1+3+5+7+9+11+13+15+17+19=(10)²=100

Similar questions