5) f(x) = tan-[ln (sin(15x2 – 30)}]
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Answered by
1
Step-by-step explanation:
f
(x)=cosx+∣
secx+tanx
secx.tanx+sec
2
x
∣−2
=cosx−2+∣secx∣
=cosx+∣secx∣−2
=cosx+
∣cosx∣
1
−2
=(
cosx
−
cosx
1
)
2
>0
Hence
f
′
(x)>0
Hence increasing.
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