Question

5. Factorise.
-12y5- y3 + y​

Answer 1

Answer:

below is your answer

hope it helps you

Step-by-step explanation:

y(1-12y^4-y^2) let y^2 =x

1-12x^2-x=-12x^2-x+1

-12x^2+4x-3x+1

=-4x(3x-1)-1(3x-1)

so 3x-1=0 and -4x-1=0

and 3y^2-1 and -4y^2-1

so factors are y ,3y^2-1 and -4y^2-1

Answer 2

Answer:

$\Large\boxed{-62y}$

Step-by-step explanation:

Given:

-12y5- y3 + y

To solve this problem, first you have to find the factors of -12y*5-y*3+y from left to right. Isolate by the y from one side of the equation.

Solutions:

First, add the numbers from left to right.

Add similar elements to the numbers from left to right.

$\displaystyle -3y+y=-2y$

$\displaystyle -12*5y-2y$

Multiply.

$\displaystyle 5*12=60$

$\displaystyle -60y-2y$

Solve.

Add numbers from left to right.

Add similar elements to the numbers from left to right.

$\displaystyle -60y-2y=\boxed{-62y}$

$\Large\boxed{-62y}$

Therefore, the correct answer is -62y.