Question

5. Factorise: (a – b)^3 + (b – c)^3 + (c – a)^3

Answer 1

x+y+z=0

(a-b)^3+(b-c)^3+(c-a)^3=0

a-b+b-c+c-a=0

0=0

So,the identity applied is x+y+z=3xyz

(a-b)^3+(b-c)^3+(c-a)^3

x + y + z =[ 3(a-b)(b-c)(c-a) ]ANS

Answer 2

Answer:

3ab....................ansss