Question

5. Factorise the expressions

a) 121b2
- 88bc + 16c2​

Answer 1

Answer:

$121 {b}^{2} - 88bc + 16 {c}^{2}$

${(11b)}^{2} - 2 \times 11b \times 4c + {(4c)}^{2}$

${(11b - 4c)}^{2}$

Answer 2

Answer:

Step-by-step explanation:

For such questions, try to look for pairs that can make complete sqaure.

Formula= (a-b)²= a²-2ab+b²

Here =>

= 121b²-88bc+16c²

= (11b)²-2(11b)(4c)+(4c)²

= (11b-4c)²       [Answer]

Keep learning!!!