Question

5. Find |3Al if
A
1 0 1
0 1 2
0 0 4
​

Answer 1

Answer:

108

Step-by-step explanation:

A = $\left[\begin{array}{ccc}1&0&1\\0&1&2\\0&0&4\end{array}\right]$

3A = $\left[\begin{array}{ccc}3&0&3\\0&3&6\\0&0&12\end{array}\right]$

|3A| = 27 { 1 [ (1*4) - (0*2) ] }

|3A| = 108