Question

5. Find a and b if
3+√6/√3+√2
= a +b √3​

Answer 1

Step-by-step explanation:

$\frac{3 + \sqrt{6} }{ \sqrt{3} + \sqrt{2} } = a + b \sqrt{3} \\ \frac{ \sqrt{3}( \sqrt{3} + \sqrt{2}) }{ \sqrt{3} + \sqrt{2} } = a + b \sqrt{3} \\ \sqrt{3} = a + b \sqrt{3}$

$a = \sqrt{3} (1 - b)$

and

$b = \frac{ \sqrt{3} - a}{ \sqrt{3} } = 1 - \frac{a}{ \sqrt{3} }$