Question

5.Find a quadratic polynomial whose zeroes are 3+
V2 and 3 – 12.​

Answer 1

Step-by-step explanation:

let a & B are zeros of given polynomial

then, a= 3+√2

and B = 3-√2 given

now a+B = 6

a.B= (3+√2)(3-√2)

=9-3=7 { we know (a+b)(a-b)=a²-b²}

required polynomial eq is

x²-(a+B)x+a.B=0

x²-6x+7=0 answer

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