5. Find an integer a such that !
(i) 5 + d = 0
(ii) a + 3 = 0
(v) 11+ a = 0
(vi) a + 0 = 0
(iii) – 12 + a = 0
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Answer:
1.5+d=0
d=0-5=-5
2.a+3=0
a=0-3= -3
5.11+a=0
a=0-11= -11
6.a+0=0
a=0
3.-12+a=0
a=0+12=12
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