Question

5 Find BC. if diameter of circle is 10 cm and AC = 6 cm

Answer 1

Answer:

Lets consider the triangle OPC

OP=OQ–PQ=5–x

PC=x

OC=AC–AD=6–5=1

OP

2

=OC

2

+PC

2

(5−x)

2

=1

2

+x

2

⟹25+x

2

–10x=x

2

+1

⟹24=10x⟹x=2.4