Question

5. Find:
(i) the area of a triangle whose three sides are 8 cm, 15 cm and 17 cm.
(ii) the altitude from the opposite vertex to the side whose length is 15 cm.
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Answer 1

Step-by-step explanation:

1. this can be done using heron's formula

s=(8+15+17)/2=40/2

=20

\sqrt{s(s - 1)(s - 2)(s - 3)}

s(s−1)(s−2)(s−3)

√20*(20-8)(20-15)(20-17)

√20*12*5*3

√3600

=60cm²

2.Length of vertex by Pythagoras therom

ABD

AB²=BD²+AD²

AD IS 1/2 OF AC

8²=BD²+7.5²

64=BD²+56.25

BD²=64-56.25

BD²=11.5

BD=√11.5

Thanks.