Question

5) Find k, if one of the root of the quadratic equation kx2 - 7x + 12 = 0 is 3.​

Answer 1

Answer:

Step-by-step explanation: Since one root the equation is 3 , therefore

x=3

p[3] = k×3×2 -7×3 +12=0

p[3]= 6k-21+12=0

p[3]=6k=9

p[3]=k=9/6

∴ vaue of k= 9/6 or 3/2

Answer 2

Answer:

p(x) = kx^2 - 7x + 12 = 0

k = 1

Step-by-step explanation:

p(x) = kx^2 - 7x + 12 = 0

p(3) = k*(3)^2 - 7*3 +12 = 0

=> 9k - 21 +12 = 0

=> 9k - 9 = 0

=> 9k = 9

=> k = 9/9

=> k = 1