Question

5. Find the altitude of the triangle whose base is 80 cm and area is 0.08 m².​

Answer 1

AnswerTriangle

Solve for height

hb=2×10-3cm

b Base

cm

A Area

cm²

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:

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Since base is given in Cms, the area also should be converted to cm .

$\[ \begin{aligned} \tt \text { Thus } 1 \text { meter }^{2} &=1 \text { metre } \times 1 \text { metre } \\ \\ & \bf=100 cm \times 100 cm \\ \\ \bf\text { Therefore } .08 \text { metre }^{2} & \bf=10000 cm ^{2} \qquad \: \: \: \: \: (\therefore 1 m =100 cm ) \\ \\ & \bf=0.08 \times 10000 Cm ^{2} \\ \\ & \color{brown} \bf=800 Cm ^{2} \end{aligned} \]$

$\[ \begin{array}{l} \text { Now the area of triangle } \tt A = \dfrac{1}{2} \times b \times h \\ \\ \text { Height of a triangle } \tt= h =\dfrac{2 A }{ b }=\dfrac{2 \times 800}{80} \\ \\ \tt \color{red} \Rightarrow \quad h =20 cm \end{array} \]$