Question

5. Find the area of a Quadrilateral, whose diagonal is 12 cm and the
perpendiculars from the opposite vertices are 4 cm and 3 cm.​

Answer 1

Answer:

42 Sq cm

Step-by-step explanation:

In quadrilateral ABCD

AC = 12 cm

DL = 4 cm

BM = 3 cm

Now in triangle ADC

Base = AC = 12

Height = DL = 4

Area = 1/2 ×b ×h

=> 1/2 × 12 × 4

=> 24 Sq cm

Again in triangle ABC

Base = AC = 12

Height = BM = 3

Area = 1/2 × b × h

=> 1/2 × 12 × 3

=> 18 Sq cm

Now total area of quad ABCD = Area of triangle ADC + Area of triangle ABC

=>( 24 + 18 ) Sq cm

=> 42 Sq cm