Question

5. Find the area of a rhombus whose side is 8 cm and whose altitude is 7 cm. If one of its
diagonals is 16 cm. find the length of the other diagonal.
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Answer 1

Step-by-step explanation:

we know that all rhombus is a parallelogram.

So, area of rhombus =base*height

=>8*7 = 56 CM sq

area of rhombus =1/2 * d1* d2

56 = 1/2* 16 *d2

112 =16 *d2

112/16 = d2

d2 = 7cm

Answer 2

Since,a rhombus is also a kind of a parallelogram.

Formula of area of rhombus =Base×Altitude

Putting values, we have

Area of rhombus =8×7=56

Since, Area of rhombus is 56 cm².

Also,formula for area of rhombus =$\frac{1}{2}×d_1d_2$

Given,Length of one diagonal =$d_1$=16

Let length of other diagonal =$d_2$

After substituting the values, we get

$56=\frac{1}{2}×16×d_2$

$56=8×d_2$

$8×d_2=56$

$d_2=\frac{56}{8}$

$d_2=7$

Hence, length of other diagonal is 7 cm.