Question

5. Find the area of a triangle if its sides are
CIF 21 am. 17 cm and 10 cm
(fr) 52 cm, 60 cm and 56 cm
( 17 cm 25 cm and 26 cm​

Answer 1

Answer:

AB=10cm

BC=21cm

CA=17cm

s= 21+17+10/2 = 48/2 = 24

Area of ΔABC=  √s(s−a)(s−b)(s−c)

=  √24(24−21)(24−17)(24−10)

=  √24×3×7×14

= 84cm ^2

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