5. Find the area of the following regular hexagon.
This question is in R.D. SHARMA CLASS 8TH .
CHAPTER----20
EXERCISE-----20.3
QUESTION ----5.
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Answers
Solution:
Given that,
NQ = 23 cm
ND + QC = 23 -13 = 10
ND = QC = 5 cm
OM = 24 cm
Area of given hexagon = 2 times Area of triangle MNO + Area of rectangle MOPR
Area of right angled triangle = 1/2 × base × altitude
Area of rectangle = length × breadth
Area of regular hexagon = 1/2 × OM × ND + MO × OP + 1/2 × RP × QC
Area of regular hexagon = 1/2 × 24 × 5 + 24 × 13 + 1/2 × 24 × 5
Area of given hexagon = 1/2 × 120 + 312 + 1/2 × 120 = 432
∴ Area of given hexagon is 432 cm2
Answer:
Find the area of the following regular hexagon.
RD Sharma Solutions for Class 8 Maths Chapter 20 – Mensuration – I (Area of a Trapezium and a Polygon) image - 22
Solution:
Given that,
NQ = 23 cm
ND + QC = 23 -13 = 10
ND = QC = 5 cm
OM = 24 cm
Area of given hexagon = 2 times Area of triangle MNO + Area of rectangle MOPR
Area of right angled triangle = 1/2 × base × altitude
Area of rectangle = length × breadth
Area of regular hexagon = 1/2 × OM × ND + MO × OP + 1/2 × RP × QC
Area of regular hexagon = 1/2 × 24 × 5 + 24 × 13 + 1/2 × 24 × 5
Area of given hexagon = 1/2 × 120 + 312 + 1/2 × 120 = 432
∴ Area of given hexagon is 432 cm2
Step-by-step explanation:
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