5. Find the area of the given figure.[JNV 2016]
16 mm
6 mm
e 8 mm
12 mm
mm
Օ|4mm
16 mm
6 mm
BC
20 mm
աա 9 Է՝
2 mm
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Answered by
17
Answer:
area of ABCP= 2(6+12) = 2(18)=36sq mm
area of DCON= 2(6+4)=2(10)=20 sq mm
area of MDEL= 2(8+14)=2(22)=44 sq mm
area of FLKG= 2(6+10)=2(16)=32 sq mm
area of GHIJK= 2(2+16)=2(18)=36 sq mm
area of the fig = 36+20+44+32+36=168 sq mm
Answered by
4
Answer:
6+12
6+4
8+14
6+10
2+16
72+24+112+60+32=300
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