Math, asked by 447327055817, 4 months ago

5.
Find the area of the triangle whose vertices are (1,2), (3, 4),(1/2,1/4)

Answers

Answered by naveenlv2008
0

Answer:

Plot the points in a rough diagram and take them in order.

Let the vertices be A(1,2),B(−3,4) and C(−5,−6)

Now the area of △ABC is

=

2

1

{(x

1

y

2

+x

2

y

3

+x

3

y

1

)−(x

2

y

1

+x

3

y

2

+x

1

y

3

)}

=

2

1

{(4+18−10)−(−6−20−6)}

=

2

1

(12+32)=22 sq.units.

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