Math, asked by arainashrivastavsphs, 5 months ago

5.Find the compound interest if the Principal is ₹.8000, rate of interest is 10 p.c.p.a and no.of years is 2 years.​

Answers

Answered by Anonymous
14

Step-by-step explanation:

Question:-

Find the compound interest if the principal is ₹8000,rate of interest is 10% p.a. and number of years is 2 years.

Answer:-

Given:-

Principal = ₹8000

Rate of interest = 10% per annum

Time = 2 years

To find :-

Compound interest

Process:-

P = ₹8000

R = 10 %

T = 2 yrs

We know that:-

Compound  \: interest \: =p \: (1 +  \frac{r}{100})n \\  = CI \: =8000(1 +  \frac{10}{100} )2 \\   \\ = CI \: =8000 \times ( \frac{110}{100}) 2 \\  \\ = \: CI \: = 8000 \times  \frac{110}{100} \times   \frac{110}{100}  \\  \\ = \: CI \:  = ₹9,680 \: (ans)

Therefore 8000 with 10% p.a. in 2 years will be 9680.

Hope it helps you...

#Be brainly

Answered by irshadkhanirsh85
1

Answer:

Question:-

Find the compound interest if the principal is ₹8000,rate of interest is 10% p.a. and number of years is 2 years.

Answer:-

Given:-

Principal = ₹8000

Rate of interest = 10% per annum

Time = 2 years

To find :-

Compound interest

Process:-

P = ₹8000

R = 10 %

T = 2 yrs

∴ We know that:-

\begin{gathered}Compound \: interest \: =p \: (1 + \frac{r}{100})n \\ = CI \: =8000(1 + \frac{10}{100} )2 \\ \\ = CI \: =8000 \times ( \frac{110}{100}) 2 \\ \\ = \: CI \: = 8000 \times \frac{110}{100} \times \frac{110}{100} \\ \\ = \: CI \: = ₹9,680 \: (ans)\end{gathered}Compoundinterest=p(1+100r)n=CI=8000(1+10010)2=CI=8000×(100110)2=CI=8000×100110×100110=CI=₹9,680(ans)

Therefore ₹8000 with 10% p.a. in 2 years will be ₹9680.

Similar questions