5.Find the compound interest if the Principal is ₹.8000, rate of interest is 10 p.c.p.a and no.of years is 2 years.
Answers
Step-by-step explanation:
Question:-
Find the compound interest if the principal is ₹8000,rate of interest is 10% p.a. and number of years is 2 years.
Answer:-
Given:-
Principal = ₹8000
Rate of interest = 10% per annum
Time = 2 years
To find :-
Compound interest
Process:-
P = ₹8000
R = 10 %
T = 2 yrs
∴ We know that:-
Therefore ₹8000 with 10% p.a. in 2 years will be ₹9680.
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Answer:
Question:-
Find the compound interest if the principal is ₹8000,rate of interest is 10% p.a. and number of years is 2 years.
Answer:-
Given:-
Principal = ₹8000
Rate of interest = 10% per annum
Time = 2 years
To find :-
Compound interest
Process:-
P = ₹8000
R = 10 %
T = 2 yrs
∴ We know that:-
\begin{gathered}Compound \: interest \: =p \: (1 + \frac{r}{100})n \\ = CI \: =8000(1 + \frac{10}{100} )2 \\ \\ = CI \: =8000 \times ( \frac{110}{100}) 2 \\ \\ = \: CI \: = 8000 \times \frac{110}{100} \times \frac{110}{100} \\ \\ = \: CI \: = ₹9,680 \: (ans)\end{gathered}Compoundinterest=p(1+100r)n=CI=8000(1+10010)2=CI=8000×(100110)2=CI=8000×100110×100110=CI=₹9,680(ans)
Therefore ₹8000 with 10% p.a. in 2 years will be ₹9680.