Question

5 Find the compound interest on rupees 4000 for 2 1/2 years at 10% per annum​

Answer 1

Answer:

Compound interest for 2.5 years is Rs. 1082.

P=4000

R=10%

Times =2.5 years

First take n=2 years

A=P(1+  

100

r

​  

)  

n

=4000(  

10

11

​  

)  

2

 

4000(  

100

121

​  

)

A=4840

Simple interest for last  

2

1

​  

 years is  

100

PRT

​  

 

=  

100

4840×10

​  

×  

2

1

​  

 

=242

Amount after 2  

2

1

​  

 year =4840+242

=5082

Compound interest =5082−4000

CI=1082.

Answer 2

Answer:

Compound interest for 2.5 years is Rs. 1082.

Step-by-step explanation: