Question

5 Find the coordinates of point which are equidistant from these two points P(3,0)
and Q(-3,0). How many points are possible satisfying this condition?​

Answer 1

Step-by-step explanation:

Given  

5 Find the coordinates of point which are equidistant from these two points P(3,0)and Q(-3,0). How many points are possible satisfying this condition?​  

• Given we need to find the coordinates of a point which are equidistant from the points P (3,0) and Q (- 3,0)
• From the graph each point on y axis is equidistant from the two points P(3,0) and Q (- 3, 0)
• Now the origin (0,0) is 3 units away from the given points P(3,0) and Q (-3,0)
• From the distance formula we have
• So d = √(x2 – x1)^2 + (y2 – y1)^2
•       = √0 – (-3)^2 + (1 – 0)^2
•      = √3^2 + 1^2
•     = √10
• So the point (0,1) is equidistant from P(-3,0). Now d = √10 and so similarly any point that lies on y axis is equidistant from p(3,0) and q(- 3,0)
• Therefore there are infinite number of co-ordinates that are equidistant from point P(3,0) and q(-3,0)

Answer 2

Answer:

root 10 is correct answer

Step-by-step explanation:

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