Question

5.Find the degree measure of the angle subtended at the centre of circle of radius 100cm by an are of length 22cm .



In exercise 3.2 in 11 maths samacheer kalvi
Tamil nadu state board
$radians = 180 \div \pi$
it is the formula used here

it is not a doubt ​

Answer 1

Answer:

Solution:

Samacheer Kalvi 11th Maths Solutions Chapter 3 Trigonometry Ex 3.2 3

Answer 2

Answer:

step by step explanation:-

We know that in a circle of radius r unit,

if an arc of length l unit subtends an angle θ radian

if an arc of length l unit subtends an angle θ radian at the centre, then

Therefore, forr = 100 cm, l = 22 cm, we have

Therefore, forr = 100 cm, l = 22 cm, we have0=22/100 radian= 180/π×22/100 degree

Therefore, forr = 100 cm, l = 22 cm, we have0=22/100 radian= 180/π×22/100 degree180×7×22/22×100degree

Therefore, forr = 100 cm, l = 22 cm, we have0=22/100 radian= 180/π×22/100 degree180×7×22/22×100degree 126/10 degree

Therefore, forr = 100 cm, l = 22 cm, we have0=22/100 radian= 180/π×22/100 degree180×7×22/22×100degree 126/10 degree12 3/5degree=12°36'

Therefore, forr = 100 cm, l = 22 cm, we have0=22/100 radian= 180/π×22/100 degree180×7×22/22×100degree 126/10 degree12 3/5degree=12°36'[1°=60']

Thus, the required angle is 12°36'

explanation:-

mark as brainlist