5. Find the difference between the greatest and the least 5-digit number that can be written using the digits 6,2,7,4,3 each only once.
6. A machine, on an average, manufacturers 2,825 screws a day . How many screws did it produce in the month of January 2006?
7. A merchant had rs 78,592 with her . She placed an order for purchasing 40 radio sets at rs 1200 each . How much money will remain with her after the purchase?
Answers
Answer:
Hello Mate !!
Step-by-step explanation:
5 .For the greatest number, we will arrange these numbers in decreasing order and for the smallest number, we will arrange in increasing order.
∴Greatest number=76432 and Smallest number=23467
Hence, difference between greatest number and smallest number=76432−23467=52965
Therefore, the difference between the greatest and the least 5-digit number that can be written using the digits 6,2,7,4,3
is 52965.
6.Janary has 31 days
So, total production of screws in january is
2,825\times31\ =\ 87,575\2,825×31 = 87,575
Therefore,
The machine will produce 87,575 screws in the month of january.
7.Cost of one radio set = Rs. 1200
Therefore, cost of 40 radio sets = Rs. 1200 × 40 = Rs. 48,000
Total amount with the merchant = Rs. 78,592
Amount spent to purchase 40 radios = Rs. 48,000
Remaining amount after purchase = Total amount - Amount spent
= Rs. (78,592 – 48,000)
= Rs. 30,592
Thanks
Please Mark as Brainliest