Question

5. Find the distance between the parallel sides of a trapezium, if the area is 175 m2
and length of parallel sides is 20 m and 15 m respectively.​

Answer 1

$\huge\bold\green{ solution }$

given ;

$area = 175m^{2}$

length of || side = 20 m and 15m

now;

$area \: of \: trapezium \: = \frac{1}{2} \times (sum \: of \: parallel \: side) \times (distance \: between \: them)$

$175 = \frac{1}{2} \times (20 + 15) \times \: h$

$175 = \frac{1}{2} \times 35 \times h \\ \\ 2(175) = 35h \: \: \\ \\ 350 = 35h \\ \\ h = \frac{350}{35} \\ \\ h = 10$

hence , prove distance b/w of trapezium = 10m

Answer 2

Answer:

10m

Step-by-step explanation:

Area of  the trapezium is equal to (1/2*( a+b)*height)

Here a = first parallel side and b is equal to 2nd parallel side.

Now ATQ

1/2*( 20+15)*h= 175

1/2*35*h = 175

h=175*2/35

h=10

So distance between the parallel sides is 10 m

Hope it will help you