5) Find the first two terms ofthe sequence for which Sn is given below
Sn=n2(n+1)2/4
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Sn=n2(n+3)
First term =T1=S1=12(1+3)=4
let T2 be the second term
So S2=T1+T2=22(2+3)=20
∴T2=20−T1=20−4=16
Hence first two terms of above sequence are 4 and 16
Note: Tn=Sn−Sn−1
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