Question

5. Find the HCF of the following by prime factorisation method: a. 144 and 180 b. 120 and 204 c. 72 and 108 d. 44 and 110​

Answer 1

Answer:

Step-by-step explanation:

This question had 192 too with 144 and 180. So here is the solution for that.

Factors of 144 = 2×2×2×2×3×3

Factors of 180 = 2×2×3×3×5

Factors of 192 = 2×2×2×2×2×2×3

Common factors of 144, 180, 192 = {2,2,3}

LCM (144,180,192) =

2×2×2×2×2×2×3×3×5 = 2880

So, HCF(144,180,192) = 2×2×3 = 12.

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