Question

5. Find the largest number that divide 256 and 212 without leaving a remainder.​

Answer 1

Answer:

Your number x has to satisfy

x≤128

128=ax+8

212=bx+12

for some integers a,b . This implies ax=120 and bx=200 , so x is a common divisor of 120 and 200 .

Since

20012080=1⋅120+80=1⋅80+40=2⋅40+0

the greatest common divisor is 40 , which is also your solution.

Answer 2

Answer:

4

Step-by-step explanation:

take HCF of 256 and 212.

you will get 2x2 as common and answer = 4.