Math, asked by puransingh87950gami, 7 months ago

5. Find the least number which after being increased by 2 is exactly divisible
by 8. 16 and 24

Answers

Answered by Anonymous
4

Answer:

Given integers,

8 , 16 and 24

Prime factorization of,

8=2³

16=2⁴

24=2³×3

LCM=product of each prime factor of highest power.

LCM=2⁴×3=48

Required number=48-2=46

Hence least number which after being increased by 2 is exactly divisible by 8 , 16 and 24 is 46.

Answered by adyapanu
0

Answer:

LCM=product of each prime factor of highest power. Hence least number which after being increased by 2 is exactly divisible by 8 , 16 and 24 is 46.08-Oct-2020

Step-by-step explanation:

FIRST OF ALL WHAT YOU HAVE TO DO IS FIND THE LCM OF 8, 16 AND 24 WHICH IS EQUALS TO 48. THEN YOU HAVE TO SUBTRACT 2 FROM 48 THAT IS 48-2= 46.

HOPE IT HELPS YOU

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