5. Find the least number which when divided by
12, 16, 24 and 36 leaves a remainder 7?
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Answer:
So we add 7 to the LCM (144+7=151). Hence the smallest number that when divided by 12 16 24 and 36 leaves a remainder 7 is 151.
Explanation:
Factors of
16 = 2x2x2x2
20 = 2x2x5
24 = 2x2x2x3
LCM = 2x2x2x2xx3x5 = 240
240+3 = 243.
The answer is 243. This number when divided by 16, 20 or 20 leaves a remainder of 3 in each case
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