Question

5. Find the length of the diagonal of a rectangle whose sides are 15 cm and 8 cm.​

Answer 1

Hey

According to pythagoreas theorem

hyp^2 = opp^2 + adj^2

Given :-

Opposite = 8cm

Adjacent = 15cm

hyp^2 = 8^2 + 15^2

hyp^2 = 64 + 225

hyp^2 = 289

hyp = 17cm

Therefore the length of the diagonal is 17cm

Answer 2

$\mathfrak{\large{\underline{\underline{Answer :-}}}}$

The Diagonal of the Rectangle is 17 cm.

$\mathfrak{\large{\underline{\underline{Explanation :- }}}}$

Given :

The Length of the Rectangle = 15 cm

Breadth of the Rectangle = 8 cm

To find :

The diagonal of the Rectangle

Solution :

Refer the Attachment for the diagram.

By Pythagoras Theorum :

Diagonal of the Rectangle is the Hypotenuse.

In ∆ ACD -

• Hypotenuse = x
• Base = 15 cm
• Height = 8 cm

★ (Hypotenuse)² = (Base)² + (Height)²

$\longrightarrow$ (x)² = (15)² + (8)²

$\longrightarrow$ x² = 225 + 64

$\longrightarrow$ x² = 289

$\longrightarrow$ x = $\sf{\sqrt{289}}$

$\longrightarrow$ x = 17

$\therefore$ The Diagonal of the Rectangle is 17 cm.