Math, asked by bhabani3124, 3 months ago


5. Find the number of positive integers n such that the highest power of 7 dividing n! is 8.

Answers

Answered by amitnrw
3

Given : positive integers n such that the highest power of 7 dividing n! is 8.​

To find : Number of Such positive integers

Solution:

highest power of 7 dividing n! is 8.​

=>  [n/7]  + [n/7²]  + [n/7³] + .+ .+ .+ . +    =  8

7² = 49 if n < 49 then

We get only  [ n/7]  where n < 49

Hence  [ n/7]  <  7

We need highest power = 8

Lets check for 49

=   [49/7]  + [49/7²]  + [49/7³] + .+ .+ .+ . +    

= 7  + 1 + 0 + 0  +

= 8

Hence n = 49 Satisfy this  

highest power of 7 dividing 49! is 8 ​

check for 55

=   [55/7]  + [55/7²]  + [55/7³] + .+ .+ .+ . +    

= 7  + 1 + 0 + 0  +

= 8

check for 56

=   [56/7]  + [56/7²]  + [55/7³] + .+ .+ .+ . +    

= 8 + 1 + 0 + 0  +

= 9

Hence 56! has power of 7 more than 8

From 1! to 55!  power of 7 is max 8

from 49! to 55!  power of 7 is exactly 8

Hence 55 positive integers

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Answered by Anonymous
0

Given :-

  • positive integers n such that the highest power of 7 dividing n! is 8.

To find :-

  • Number of Such positive integers

Solution:-

highest power of 7 dividing n! is 8.

=>  [n/7]  + [n/7²]  + [n/7³] + .+ .+ .+ . +    =  8

7² = 49 if n < 49 then

We get only  [ n/7]  where n < 49

Hence  [ n/7]  <  7

We need highest power = 8

Lets check for 49

=   [49/7]  + [49/7²]  + [49/7³] + .+ .+ .+ . +    

= 7  + 1 + 0 + 0  +

= 8

Hence n = 49 Satisfy this  

highest power of 7 dividing 49! is 8

check for 55

=   [55/7]  + [55/7²]  + [55/7³] + .+ .+ .+ . +    

= 7  + 1 + 0 + 0  +

= 8

check for 56

=   [56/7]  + [56/7²]  + [55/7³] + .+ .+ .+ . +    

= 8 + 1 + 0 + 0  +

= 9

Hence 56! has power of 7 more than 8

From 1! to 55!  power of 7 is max 8

from 49! to 55!  power of 7 is exactly 8

Hence 55 positive integers

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