Question

5. Find the rate of interest when :

ii) Rs 300 amounts to Rs 400 in 2 years

6. Find the time when:

ii) Rs 6540 amounts to Rs 8447.50 at
12 1/2 per annum​

Answer 1

Answer:

Rate= 16$\frac{2}{3}$ % p.a

Time=  2 years, 4 months.

Step-by-step explanation:

1) Principal= Rs 300

Amount= Rs 400

SI= Amount - Principal=  400- 300=  Rs 100

Rate of interest= SI X 100 / P X T

                         = 100 X 100 / 300 X 2 = 50/3 % = 16$\frac{2}{3}$ % p.a ( Mixed fraction)

2) Principal= Rs 6540

Amount= Rs 8447.50

SI= Amount - Principal= 8447.50 - 6540.00= 1907.50

Rate= 12 $\frac{1}{2}$ %= 25/2 % ( Mixed fraction)

Time= SI X 100 / P X R

         = 1907.50 X 100 X 2 / 6540 X 25 ( 25/2 - Reciprocal )

         = 3815/ 1635=  7/3=  2$\frac{1}{3}$ yrs=  2 years, 4 months.

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Answer 2

Answer:

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